soal jawab listrik tentang kemagnetan

1.     The pole face of a magnet is 3 cm by 2 cm and it produces a flux of 30µWb. Calculate the flux density at the pole face.

A = 3 x 2 x 10-4 m2; ɸ = 30 x 10-6

Answer:

B = ɸ/A
   = 30 x 10-6 / 6 x 10-4
   = 0,05 tesla
   = 50 mT

2.     Calculate the excitation current required in a 600 turn coil in order to produce an mmf of 1500 At.

N = 600 ; F = 1500 At

Answer:

F = NI
I = F/N
  = 1500/600
  = 2.5 A

3.     A 1500 turn coilis uniformly wound araound an iron toroid of uniform csa 5 cm2. Calculate mmf and  flux density producedif the resulting flux is 0.2 mWb when the coil current is 0.75 A.

N = 1500; A = 5 x 10-4 m2;  ɸ = 0,2 x 10-3Wb; I=0.75 A

Answer:

F = NI
   = 1500  x 0.75
   = 1125 At

B = ɸ / A
   = 0.2 x 10-3 / 5 x 10-4
   = 0.4 T

4.     A current of 400 mA is passed through a 550 turn coil wound on a toroid of mean diameter 8 cm.

I = 0,4 A ; N = 550 ; d = 8 x 10-2 m

Answer:

Ɩ = πd
  = 3,14 x 8 x 10-2 
  = 0,251 m

H = NI / Ɩ
   = 550 X 0,4 / 0.251
   = 875.35 At/m

5.     An iron toroid having a mean radius of 0.1 m and csa of π cm2 is wound with a 1000 turn coil the coil current results in a flux of 0.1775 mWb in the toroid . using the following data, determine
a.     The coil current and
b.     The relative permeability of the toroid under these conditions.

H(At/m)        80       85       90       95       100
B(T)                0.5      0.55   0.58   0.59   0.6

Answer:

B = ɸ / A
   = 0.1775 x 10-3 / π x 10-4
   = 0.565 T

And from the plotted graph, when B = 0.565T, H = 88 At/m

a.     Now, the lengt of the toroid, Ɩ = 2πr = 0.628 m

H = NI / Ɩ
 I = HƖ / N
   = 88 x 0.628 / 1000
   = 0.0553 A
   = 55.3 Ma

b.     B  = µ0µr H
µr = B / µOH
     = 0.565 / 4π x 10-7 x 88

    = 5109

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